# Newton's Method for Finding Roots: A Simple and Powerful Algorithm  ## Introduction

In mathematics, finding roots of a given function is a fundamental problem that has been studied for centuries. The roots of a function are the values of the input variable (or variables) that make the function equal to zero. These roots play an important role in many applications, such as optimization, signal processing, and physics.

One of the most well-known methods for finding roots is Newton's method, sometimes also called the Newton-Raphson method. Newton's method is a simple yet powerful algorithm that can find roots of a wide range of functions, including both linear and non-linear functions. In this article, we will discuss the basic theory behind Newton's method and provide a step-by-step guide on how to apply it in practice.

## Newton's Method: Theory

Suppose we have a function f(x) that we want to find the roots of. The first step in Newton's method is to make a guess of the root, which we can call x_0. We then draw a tangent line to the curve of f(x) at the point (x_0, f(x_0)). This tangent line intersects the x-axis at a point that we can call x_1. This point represents a better guess of the root than x_0, because it is closer to the actual root. We repeat this process, drawing a tangent line to the curve of f(x) at the point (x_1, f(x_1)), and finding the intersection point with the x-axis. Each time we repeat this process, we get a better and better guess of the root.

The mathematical formula for the iteration step at each iteration n, where x_n is our current guess of the root, is given by:

x_{n+1} = x_n - f(x_n)/f'(x_n)

Here, f'(x_n) is the derivative of f(x) evaluated at x_n. This formula is derived from the fact that the slope of the tangent line to the curve of f(x) at the point (x_n, f(x_n)) is equal to f'(x_n). Therefore, the x-intercept of this tangent line is given by x_n - f(x_n)/f'(x_n).

## Example

To illustrate Newton's method, let's consider the function f(x) = x^3 - 5x^2 + 3x + 7. Our goal is to find a root of this function.

We can start by making a guess of the root, say x_0 = 2. We then compute the value of f(x_0), which is f(2) = 3. We also compute the value of f'(x_0), which is f'(2) = 7. Using these values, we can apply the iteration formula to get our next guess of the root:

x_1 = x_0 - f(x_0)/f'(x_0) = 2 - 3/7 = 1.5714

We can repeat this process, using x_1 as our new guess of the root:

x_2 = x_1 - f(x_1)/f'(x_1) = 1.5714 + 0.3024 = 1.8738

We can continue this process until we reach a desired level of accuracy. In this case, we can stop after six iterations, when our guess of the root has converged to x = 1.7932. This is indeed a root of the function f(x), since f(1.7932) is very close to zero.