1968 Wimbledon Championships – Girls' singles

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Girls' singles
1968 Wimbledon Championships
ChampionUnited States Kristy Pigeon
Runner-upAustralia Lesley Hunt
Score6–4, 6–3
Draw25

Kristy Pigeon defeated Lesley Hunt in the final, 6–4, 6–3 to win the girls' singles tennis title at the 1968 Wimbledon Championships.[1]

Draw

Key

Finals

Semifinals Final
          
Australia Lesley Hunt 6 6
Sweden Maria Strandberg 1 2
Australia Lesley Hunt 4 3
United States Kristy Pigeon 6 6
United States Kristy Pigeon 6 6
Japan Kazuko Sawamatsu 1 1

Top half

First round Second round Quarterfinals Semifinals
Austria E Lehner 1 1
Australia Lesley Hunt 6 6
Australia L Hunt 8 6
United Kingdom V Burton 6 4
Israel Paulina Peisachov 2 2
United Kingdom Veronica Burton United Kingdom V Burton 6 6
Monaco L Vanderpol w/o Australia L Hunt 6 6
Socialist Federal Republic of Yugoslavia Alenka Pipan 0 6 7 Sweden M Strandberg 1 2
Venezuela A Connelly 6 1 5 Socialist Federal Republic of Yugoslavia A Pipan 4 6 2
Italy Daniela Porzio 6 6 Italy D Porzio 6 3 6
Greece A Koutsouris 2 3 Italy D Porzio 4 4
Sweden Maria Strandberg 6 6 Sweden M Strandberg 6 6
Republic of Ireland Nora McMordie 1 2 Sweden M Strandberg 6 4 6
Switzerland E Bucher 4 2 Belgium C Vangheluwe 1 6 3
Belgium C Vangheluwe 6 6

Bottom half

First round Second round Quarterfinals Semifinals
Uruguay Fiorella Bonicelli w/o
Soviet Union Zaiga Jansone Soviet Union Z Jansone 6 6
Czechoslovakia Mirka Koželuhová 2 12 West Germany S Thunig 1 3
West Germany S Thunig 6 14 Soviet Union Z Jansone 4 1
Norway H Hancke 2 1 United States K Pigeon 6 6
United States Kristy Pigeon 6 6 United States K Pigeon 6 6
Brazil MC Diaz 3 6 6 Brazil MC Diaz 1 0
Denmark D Ekner 6 3 3 United States K Pigeon 6 6
Japan K Sawamatsu 1 1
Hungary A Gráczol 2 0
Japan Kazuko Sawamatsu 6 6
Japan K Sawamatsu 6 6
Mexico P Montaño 3 2
Sweden Nina Blom 1 1
Mexico P Montaño 6 6

References

  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.